In the figure the value of resistor R is (25 + I/2) Ω where I is the current in amperes. The current I is

This question was previously asked in

UJVNL AE EE 2016 Official Paper

Option 1 : 10 A

**Concept:**

**Ohm’s law:**

At constant temperature, the current flowing through a resistance is directly proportional to the potential difference across its end.

I ∝ V

\(I=\frac{1}{R}\times V\)

V = I R

Where V = the potential difference, R = resistance, and I = current flowing.

**Calculation:**

R = (25 + I/2) Ω

From Ohm's law

\(300 = I \times \left( {25 + \frac{I}{2}} \right)\)

On solving the above equation

I^{2} + 50 I - 600 = 0

(I - 10) (I + 60) = 0

**I = 10 A**